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Solution
∠1 = 55°
∠2 + ∠3 = 20° + 35° = 55°
∴ ∠1 = ∠2 + ∠3 = 55°
i.e. ∠ABM = ∠BMN = 55°
=> AB ∥ MN ( ∵ Alternate interior angles are equal lines are parallel ) - (1)
Also ∠3 + ∠4 = 35° + 145° = 180°
=> CD ∥ MN - (2)
From (1) and (2)
AB ∥ CD
Solution
4 (216)-2/3 ₋ 1 (256)-3/4
4 {(6)3}-2/3 ₋ 1 (44)-3/4
4 6-2 ₋ 4 4-3
= 4 x 62 - 43
= 144 - 64
= 80
Solution
We know that (a - b)3 = a3 - b3 - 3ab(a - b)
= a3 - b3 - 3a2b + 3ab2
∴ (5x - 7y)3 = (5x)3 - (7y)3 - 3(5x)2 x 7y + 3(5x)(7y)2
= 125x3 - 343y3 - 525x2y + 735xy2
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